Optimal. Leaf size=320 \[ \frac{c^{3/2} \sqrt{d} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{d} \sqrt{c \sin (a+b x)}}\right )}{4 \sqrt{2} b}-\frac{c^{3/2} \sqrt{d} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{d} \sqrt{c \sin (a+b x)}}+1\right )}{4 \sqrt{2} b}-\frac{c^{3/2} \sqrt{d} \log \left (-\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}+\sqrt{d} \cot (a+b x)+\sqrt{d}\right )}{8 \sqrt{2} b}+\frac{c^{3/2} \sqrt{d} \log \left (\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}+\sqrt{d} \cot (a+b x)+\sqrt{d}\right )}{8 \sqrt{2} b}-\frac{c \sqrt{c \sin (a+b x)} (d \cos (a+b x))^{3/2}}{2 b d} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.280711, antiderivative size = 320, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.32, Rules used = {2568, 2575, 297, 1162, 617, 204, 1165, 628} \[ \frac{c^{3/2} \sqrt{d} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{d} \sqrt{c \sin (a+b x)}}\right )}{4 \sqrt{2} b}-\frac{c^{3/2} \sqrt{d} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{d} \sqrt{c \sin (a+b x)}}+1\right )}{4 \sqrt{2} b}-\frac{c^{3/2} \sqrt{d} \log \left (-\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}+\sqrt{d} \cot (a+b x)+\sqrt{d}\right )}{8 \sqrt{2} b}+\frac{c^{3/2} \sqrt{d} \log \left (\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}+\sqrt{d} \cot (a+b x)+\sqrt{d}\right )}{8 \sqrt{2} b}-\frac{c \sqrt{c \sin (a+b x)} (d \cos (a+b x))^{3/2}}{2 b d} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2568
Rule 2575
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int \sqrt{d \cos (a+b x)} (c \sin (a+b x))^{3/2} \, dx &=-\frac{c (d \cos (a+b x))^{3/2} \sqrt{c \sin (a+b x)}}{2 b d}+\frac{1}{4} c^2 \int \frac{\sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}} \, dx\\ &=-\frac{c (d \cos (a+b x))^{3/2} \sqrt{c \sin (a+b x)}}{2 b d}-\frac{\left (c^3 d\right ) \operatorname{Subst}\left (\int \frac{x^2}{d^2+c^2 x^4} \, dx,x,\frac{\sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{2 b}\\ &=-\frac{c (d \cos (a+b x))^{3/2} \sqrt{c \sin (a+b x)}}{2 b d}+\frac{\left (c^2 d\right ) \operatorname{Subst}\left (\int \frac{d-c x^2}{d^2+c^2 x^4} \, dx,x,\frac{\sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{4 b}-\frac{\left (c^2 d\right ) \operatorname{Subst}\left (\int \frac{d+c x^2}{d^2+c^2 x^4} \, dx,x,\frac{\sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{4 b}\\ &=-\frac{c (d \cos (a+b x))^{3/2} \sqrt{c \sin (a+b x)}}{2 b d}-\frac{\left (c^{3/2} \sqrt{d}\right ) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt{d}}{\sqrt{c}}+2 x}{-\frac{d}{c}-\frac{\sqrt{2} \sqrt{d} x}{\sqrt{c}}-x^2} \, dx,x,\frac{\sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{8 \sqrt{2} b}-\frac{\left (c^{3/2} \sqrt{d}\right ) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt{d}}{\sqrt{c}}-2 x}{-\frac{d}{c}+\frac{\sqrt{2} \sqrt{d} x}{\sqrt{c}}-x^2} \, dx,x,\frac{\sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{8 \sqrt{2} b}-\frac{(c d) \operatorname{Subst}\left (\int \frac{1}{\frac{d}{c}-\frac{\sqrt{2} \sqrt{d} x}{\sqrt{c}}+x^2} \, dx,x,\frac{\sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{8 b}-\frac{(c d) \operatorname{Subst}\left (\int \frac{1}{\frac{d}{c}+\frac{\sqrt{2} \sqrt{d} x}{\sqrt{c}}+x^2} \, dx,x,\frac{\sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{8 b}\\ &=-\frac{c^{3/2} \sqrt{d} \log \left (\sqrt{d}+\sqrt{d} \cot (a+b x)-\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{8 \sqrt{2} b}+\frac{c^{3/2} \sqrt{d} \log \left (\sqrt{d}+\sqrt{d} \cot (a+b x)+\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{8 \sqrt{2} b}-\frac{c (d \cos (a+b x))^{3/2} \sqrt{c \sin (a+b x)}}{2 b d}-\frac{\left (c^{3/2} \sqrt{d}\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{d} \sqrt{c \sin (a+b x)}}\right )}{4 \sqrt{2} b}+\frac{\left (c^{3/2} \sqrt{d}\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{d} \sqrt{c \sin (a+b x)}}\right )}{4 \sqrt{2} b}\\ &=\frac{c^{3/2} \sqrt{d} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{d} \sqrt{c \sin (a+b x)}}\right )}{4 \sqrt{2} b}-\frac{c^{3/2} \sqrt{d} \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{d} \sqrt{c \sin (a+b x)}}\right )}{4 \sqrt{2} b}-\frac{c^{3/2} \sqrt{d} \log \left (\sqrt{d}+\sqrt{d} \cot (a+b x)-\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{8 \sqrt{2} b}+\frac{c^{3/2} \sqrt{d} \log \left (\sqrt{d}+\sqrt{d} \cot (a+b x)+\frac{\sqrt{2} \sqrt{c} \sqrt{d \cos (a+b x)}}{\sqrt{c \sin (a+b x)}}\right )}{8 \sqrt{2} b}-\frac{c (d \cos (a+b x))^{3/2} \sqrt{c \sin (a+b x)}}{2 b d}\\ \end{align*}
Mathematica [C] time = 0.0699715, size = 67, normalized size = 0.21 \[ \frac{2 \sqrt [4]{\cos ^2(a+b x)} \tan (a+b x) (c \sin (a+b x))^{3/2} \sqrt{d \cos (a+b x)} \, _2F_1\left (\frac{1}{4},\frac{5}{4};\frac{9}{4};\sin ^2(a+b x)\right )}{5 b} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [C] time = 0.078, size = 654, normalized size = 2. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \cos \left (b x + a\right )} \left (c \sin \left (b x + a\right )\right )^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]